I’m trying to save a node (with the normal node form) via an ajax callback. The first save works. But after that I want to return the same node form again so that the user can update the values and save the node again. But this second save attempt fails. I always get a message like “this form has already been submitted”. Are any solutions for this problem? Or shall I write a custom JS menu hook which saves the node programmatically?

Here are the relevant parts of my module

function MYMODULE_form_finding_node_form_alter (&$form, &$form_state){   $form['#prefix'] = '<div id="wrapper">';   $form['#suffix'] = '</div>';   $form['actions']['submit']['#ajax'] = array(     'callback' => 'MYMODULE_finding_node_form_submit_ajax',     'wrapper' => 'finding-form-wrapper'   ); }   function MYMODULE_finding_node_form_submit_ajax($form, &$form_state){   $form_id = '#' . str_replace('_','-',$form['#form_id']);   $commands = array();   $commands[] = ajax_command_remove('.l-messages');   if(form_get_errors()){     $commands[] = ajax_command_replace($form_id, '<div id="finding-form-wrapper"></div>');     $commands[] = ajax_command_replace('#finding-form-wrapper', drupal_render($form));   }   else{     $node = $form_state['node'];     $form_state = array();     $form_state['rebuild'] = TRUE;     $form_state['build_info']['args'] = array($node);     $form = drupal_build_form('finding_node_form', $form_state);     $form['#id'] = str_replace("_", "-", $form_id);      $commands[] = ajax_command_replace($form['#id'], drupal_render($form));   }   $commands[] = ajax_command_prepend('.page', '<section class="l-messages row"><div class="columns">' . theme('status_messages') . '</div></section>');   return array('#type' => 'ajax', '#commands' => $commands); }